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Construction: Scaling a line, triangle, polygon, circle


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overview

In this page, the following are covered

dividing a line in a given ratio (The method employed is based on properties of similar triangles.) dividing a line using similar triangles
scaling or dividing a line in a given ratio (The method employed uses properties of traversal of pair of parallels.) dividing a line using traversal of parallels
scaling a triangle in a given ratio scale-down a triangle scale-up a triangle
scaling a polygon in a given ratio scaling a quadrilateral
scaling a circle scaling a circle

problem

dividing a line

Given a line segment AB¯, it is required to mark a point P such that, AP¯:PB¯=m:n. That is, the AB¯ is divided to AP¯ and PB¯ in m:n ratio.

To achieve that, we use properties of similar triangles.

dividing a line using similar triangles

A set of similar triangles are formed with AB¯ as one of its sides. The formulation is shown in the figure. In such a construction, the following properties are noted.

 •  AB¯:AP¯=AD¯:AC¯

 •  EB¯CP¯

The construction is explained in following pages.

dividing a line using similar triangles

The construction is visualized in the following.

 •  Construct a ray AR at an angle, of any measurement.

 •  In a compass, take a measurement

 •  Using the compass, mark a number of segments on the ray.

 •  Construct line D to B

 •  Construct a line through the the point C

 •  The point of intersection of the line through C and AB¯ is marked P.

dividing a line using similar triangles

The figure illustrates 3 different angles AR1, AR2, and AR3. The procedure to construct will work for any arbitrary measure of angle.

dividing a line using similar triangles

Continuing on dividing line segment AB¯ in ratio AP¯:PB¯=2:1. The construction is visualized in the following.

 •  Construct a ray AR at an angle

 •  In a compass, take a measurement. Any arbitrary length will do fine.

 •  Using the compass, mark a number of segments on the ray.

 •  Construct line D to B

 •  Construct a line through the the point C

 •  The point of intersection of line through C and AB¯ is marked P.

dividing a line using similar triangles

Continuing on dividing AB¯ in ratio 2:1. The figure illustrates 3 different measures on compass. The procedure to construct will work for any arbitrary length.

dividing a line using similar triangles

Continuing on dividing line segment AB¯ in ratio AP¯:PB¯=2:1. The construction is visualized in the following.

 •  Construct a ray AR at an angle

 •  In a compass, take a measurement

 •  Using the compass, mark a number of segments on the ray. To achieve 2:1, sum of 2 and 1 = 3 segments are marked.,

 •  Construct line D to B

 •  Construct a parallel to DB¯ through the the point C

 •  The point of intersection of parallel through C and AB¯ is marked P.

dividing a line using similar triangles

Continuing on dividing AB¯ in ratio 2:1. The lines through points C1, C2, and C3 are parallel to D1B¯, D2B¯, and D3B¯ respectively. By the rules of similar triangles, the lines intersect at point P.

dividing a line using similar triangles

The construction is visualized in the following.

 •  Construct a ray AR at an angle

 •  In a compass, take a measurement

 •  Using the compass, mark a number of segments on the ray.

 •  Construct line D to B

 •  Construct a parallel to DB¯ through the point C

 •  The point of intersection of the parallel through C and AB¯ is marked P.

The ratio AP¯:PB¯ is same as the ratio AC¯:CD¯, which is 2:1

summary

dividing a line using similar triangles

Segmenting a line in a given ratio (Triangle Method): Use the property of similar triangles the given line can be segmented. Given AB¯ to be divided in ratio m:n.

The triangle ABD is constructed with AD¯ having m+n segments. By using the first m segments, the similar triangle ACP is created.

Since, AC¯:CD¯ is m:n, by the similarity property of triangle, AP¯:PB¯=m:n

segmenting a line

The objective is to divide the given line AB¯ in ratio m:n. The properties of similar triangles help in acheiving that.

dividing a line using traversal of parallels

A set of similar triangles are formed with AB¯ and a pair of parallel lines. The formulation is shown in the figure. In such a construction, the following properties are noted.

 •  AD¯BC¯

 •  AP¯:AE¯=PB¯:BF¯

The construction is explained in the following pages.

dividing a line using traversal of parallels

The objective is to divide the given line AB¯ in ratio AP¯:PB¯=1:2.

The construction is visualized in the following.

 •  Construct a ray BC at an angle. Any angles will do fine.

 •  Construct another ray AD in parallel to BC.

 •  In a compass, take a measurement. Any arbitrary length will do fine.

 •  Using the compass, mark a number of segments on the rays AD and BC marking points E and F.

 •  Construct line E to F

 •  The point P is marked at the intersection of EF¯ and AB¯.

dividing a line using traversal of parallels

The figure illustrates 3 different angles. The procedure will work for any arbitrary measure of angle.

dividing a line using traversal of parallels

The construction is visualized as given below.

 •  Construct a ray BC at an angle

 •  Construct another ray AD in parallel to the BC.

 •  In a compass, take an arbitrary length on the compass

 •  Using the compass, mark a number of segments on the rays AD and BC marking points E and F.

 •  Construct line E to F

 •  The point P is marked at the intersection of EF¯ and AB¯.

dividing a line using traversal of parallels

The figure illustrates 3 different measures on compass AE1¯, AE2¯, AE3¯. The procedure to construct will work for any arbitrary length.

dividing a line using traversal of parallels

Continuing on dividing AB¯ in ratio AP¯:PB¯=1:2.

 •  Using the measure on the compass, mark a number of segments on the rays AD and BC marking points E and F. To achieve 1:2 ratio, the points are marked with 1 segment on AD and 2 segments on BC

From the properties of similar trianges, AP¯:PB¯=1:2, same as the ratio AE¯:BF¯.

summary

dividing a line using traversal of parallels

Segmenting a line in a given Ratio (Traversal of pair of parallels) : Use the properties of angles in the traversal of parallel lines and the similar triangles, the given line can be segmented. Given AB¯ to be divided in ratio m:n.

The parallels AD and BC are constructed.

Mark points E and F in the given ratio m:n. Since AE¯:BF¯ is in the given ratio m:n, by the similarity property of triangles, AP¯:PB¯=m:n

scale-down a triangle

Consider the given ABC. The objective is to construct APQ such that the corresponding sides are in ratio 3:2. To achieve that, the first step is to divide the side AB¯ to mark point P. Then PQ¯ can be constructed to complete APQ.

scaling a triangle

Considering scaling the given ABC to APQ in the ratio 3:2. The given ratio is for the corresponding sides of the triangles, i.e. AB¯:AP¯. But to divide the AB¯, the ratio is modified to AP¯:PB¯=2:1.

scaling a triangle

Considering scaling the given ABC to APQ in the ratio 3:2. The figure illustrates the solution. The AB¯ is segmented to AP¯ and PB¯. This marks the point P.

To mark Q, construct the line PQ¯ in parallel to BC¯.

summary

scaling a triangle

Scaling a Triangle:The figure illustrates the solution. The AB¯ is segmented to AP¯ and PB¯. This marks the point P.

The PQ¯ is constructed in parallel to BC¯.

APQ is constructed.

scale-up a triangle

Consider the given ABC. The objective is to construct APQ such that the corresponding sides are in the ratio 2:3. To achieve that, one of the sides can be scaled-up to construct similar triangles.

Scale-up the side AB¯ to mark point P;. Then PQ¯ can be constructed to complete APQ.

scaling a triangle

Considering scaling the given ABC to APQ in the ratio 2:3. The given ratio is for the corresponding sides of the triangles, i.e. AB¯:AP¯. But to scale the AB¯, the ratio is modified to AB¯:BP¯=2:1.

scaling a triangle

The figure illustrates the solution. The AB¯ is scaled to AB¯ and BP¯. This marks the point P. To mark Q, construct the line PQ¯ in parallel to BC¯ and extend AC¯.

The figure illustrates the solution. The AB¯ is scaled up to AB¯ and BP¯. This marks the point P.

The AC¯ is extended to the ray AT. The PQ¯ is constructed in parallel to BC¯ and that meets AT.

APQ is constructed.

summary

scaling a triangle

Scaling of Triangles : To scale a triangle, scale one of the sides and use the properties of similar triangles to construct the scaled triangle.

scaling quadrilateral

scaling a quadrilateral

Consider the given quadrilateral ABCD. The objective is to construct the quadrilateral APRQ such that the corresponding sides are in ratio 3:2. To achieve that, divide the sides, to mark points P and Q and construct parallels to mark point R.

scaling a quadrilateral

Consider the given quadrilateral ABCD. The objective is to construct the quadrilateral APRQ such that the corresponding sides are in ratio 3:2.

The following steps details construction of the quadrilateral APRQ.

 •  Divide the side AB to 2:1 ratio to mark point P.

 •  Divide the side AD to 2:1 ratio to mark point Q.

 •  Construct two rays PR and QR in parallel to BC¯ and DC¯ respectively.

 •  The point of intersection is point R.

Quadrilateral APRQ is constructed.

scaling a quadrilateral

Consider the given quadrilateral ABCD. The objective is to construct the quadrilateral APRQ such that the corresponding sides are in ratio 2:3. To achieve that scale-up the sides, to mark points P and Q and construct parallels to mark point R

scaling a quadrilateral

Consider the given quadrilateral ABCD. The objective is to construct the quadrilateral APRQ such that the corresponding sides are in ratio 2:3

The following steps details construction of the quadrilateral APRQ.

 •  Scale-up the side AB to 2:1 ratio to mark point P.

 •  Scale-up the side AD to 2:1 ratio to mark point Q.

 •  Construct two rays PR and QR in parallel to BC¯ and DC¯ respectively.

 •  The point of intersection is point R

Quadrilateral APRQ is constructed.

summary

scaling a quadrilateral

Scaling of Polygons : To scale a polygon, scale a side and construct a parallel to the next side and scale the side in the parallel. Continue this with all the sides to complete scaling the given polygon.

scaling a circle

scaling a circle

Consider the given circle A centered at point O. The objective is to construct circle B such that the radius are in ratio 3:2. To achieve that, construct a radius and divide it in 2:1 ratio

scaling a circle

Consider the given circle A centered at point O. The objective is to construct circle B such that the radius are in ratio 3:2

The following steps detail scaling a circle.

 •  Construct a radius OP¯.

 •  Scale the radius in ratio 2:1 to mark point Q.

 •  Construct a circle with radius OQ¯. Scaled Circle B is constructed.

summary

scaling a circle

Scaling a Circle : To scale a circle, scale a radius as per scaling a line segment. The scaled circle is constructed with scaled line segment as the radius.

Outline

The outline of material to learn "Consrtruction (High school)" is as follows.

Note: Click here for detailed overview of "Consrtruction (High school)"

Note 2: click here for basics of construction, which is essential to understand this.

    →   Construction of Triangles With Secondary Information

    →   Construction: Scaling a line, triangle, polygon, circle

    →   Construction of Tangents and Chord for a circle